Question #12738
What is the mass of sodium phosphate (163.94 g/mol) that yields 1.00 g of calcium phosphate (310.18 g/mol) precipitate?
__CaCl2(s) + __Na3PO4(aq) → __Ca3(PO4)2(s) + __NaCl(aq)
__CaCl2(s) + __Na3PO4(aq) → __Ca3(PO4)2(s) + __NaCl(aq)
Expert's answer
m 1.00
3
CaCl2(aq) + 2 Na3PO4(aq) --> Ca3(PO4)2(s) + 6 NaCl(aq)
2*163.94 310.18
m=2*163.94*1.00/310.18=1.057g
3
CaCl2(aq) + 2 Na3PO4(aq) --> Ca3(PO4)2(s) + 6 NaCl(aq)
2*163.94 310.18
m=2*163.94*1.00/310.18=1.057g
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#339914 on Dec 2023
#339914 on Dec 2023