Question #12730

How many formula units of sodium sulfate are in 0.333 mol of Na2SO4?

Expert's answer

Taking into consideration that Avogadro constant (NA)(\mathrm{N}_{\mathrm{A}}) is 6.02214129(27)×1023mol−16.02214129(27)\times 10^{23}\mathrm{mol}^{-1}, formula units of sodium sulfate in 0.333 moles of Na2SO4\mathrm{Na_2SO_4} are:


N(Na2SO4)=NA⋅n(Na2SO4)=6.02214129(27)×1023mol−1⋅0.333mol=2⋅1023\mathrm{N} \left(\mathrm{Na_2SO_4}\right) = \mathrm{N_A} \cdot \mathrm{n} \left(\mathrm{Na_2SO_4}\right) = 6.02214129(27) \times 10^{23} \mathrm{mol}^{-1} \cdot 0.333 \mathrm{mol} = 2 \cdot 10^{23}


units.

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