Answer to Question #125450 in Chemistry for Henry king .S

Question

A given mass of a gas occupies 850cm3 at 320K and 0.92×105 Nm-2 pressure. Calculate the volume of the gas at S.T.P.

Answer 1

P₁ = 0.92×10⁵ N m^-2 = 0.92×10⁵ Pa = 92000 Pa

V₁ = 850 cm³ = 0.85 L

T₁ = 320 K

P₂ = 101325 Pa (STP)

V₂ = unknown

T₂ = 273.15 K (STP)

 

Solution:

The Combined Gas Law:

P₁V₁/T₁ = P₂V₂/T₂

Cross-multiply to clear the fractions:

P₁V₁T₂ = P₂V₂T₁

Divide to isolate V₂:

V₂ = (P₁V₁T₂) / (P₂T₁)

Plug in the numbers and solve for V₂:

V₂ = (92000 Pa × 0.85 L × 273.15 K) / (101325 Pa × 320 K) = 0.659 L = 659 mL = 659 cm³

V₂ = 659 cm³

Answer: 659 cm³ is the volume of the gas at STP.