The reaction between hydrogen and oxygen can be calculated as following:
H2 +O2 = H2O
First, the number of moles of the reactants must be calculated. As 1 mol of any gas occupies 22.4 L:
n(oxygen) = V(oxygen) / 22.4 L/mol = 200 cm3 / 22.4 L/mol = 0.2 L / 22.4 L/mol = 0.009 mol
n(hydrogen) = V(hydrogen) / 22.4 L/mol = 100 cm3 / 22.4 L/mol = 0.1 L / 22.4 L/mol = 0.0045 mol
As a result, hydrogen is a limiting reactant. Therefore, during the explosion, 0.0045 mol of hydrogen and 0.0045 / 2 = 0.00225 mol of oxygen will be used. From here, 0.009 mol - 0.00225 mol = 0.00675 mol of oxygen will be left.
Finally, the volume of oxygen left is:
V(left oxygen) = 0.00675 mol × 22.4 L/mol = 0.15 L = 150 cm3
Answer: 150 cm3
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