Answer to Question #122494 in Chemistry for Mahanoor fakhar

Question

10.00grams of magnesium acetate is dissolved in 100.00 ml of DI water . The molar mass is 142.41g/mol . Calculate the molarity

Answer 1

Solution:

Molarity = mol solute / L of solution

Magnesium acetate = Mg(C₂H₃O₂)₂

Moles of Mg(C₂H₃O₂)₂ = Mass of Mg(C₂H₃O₂)₂ / Molar mass of Mg(C₂H₃O₂)₂

Moles of Mg(C₂H₃O₂)₂ = (10.00 g) / (142.41 g/mol) = 0.07022 mol

mol solute = 0.07022 mol

L of solution = 100.00 mL = 0.1000 L

Therefore,

Molarity of Mg(C₂H₃O₂)₂ = (0.07022 mol) / (0.1000 L) = 0.7022 mol/L = 0.7022 M

Answer: The molarity of magnesium acetate is 0.7022 M.