In order to prepare = 5 L of = 6.000 M H3PO4 solution, one needs the following quantity of H3PO4:
mol.
The mass of this quantity of H3PO4 can be calculated using the molar mass of H3PO4 (98.00 g/mol):
g.
Thus, the mass of the concentrated solution needed contains 2940 g of H3PO4:
g.
The specific gravity of the concentrated solution is 1.69 g/mL. Therefore, 3454.8 g of the concentrated solution corresponds to the following volume:
mL.
Then, to 2044 mL of the concentrated solution one needs to add the following volume of water:
mL.
Finally, in order to prepare 5 L of 6.000 M of H3PO4 from a concentrated solution
that is 85.1%(m/m) and has a specific gravity of 1.69 g/mL, one needs to take 2044 mL of the concentrated solution and add 2956 mL of water.
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