[H2] = [I2] = 0.200 M
Kc = 57.0
Solution:
The balanced chemical equation:
H2(g) + I2(g) ⇌ 2HI(g)
The equilibrium expression for this reaction:
Therefore,
[HI]2 = [H2] × [I2] × Kc
[HI]2 = (0.200 M) × (0.200 M) × (57.0)
[HI]2 = 2.28 M2
[HI] = (2.28 M2)0.5 = 1.51 M
[HI(g)] = 1.51 M
Answer: 1.51 M is the molar concentration of HI at equilibrium.
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