Question

0.00285 kg of C2H6 (g) = ? mL (STP)


Answer needs to be In mL

Answer 1

0.00285 kg of C₂H₆ = 2.85 g of C₂H₆

Solution:

At STP, one mole of any gas occupies a volume of 22.4 L

The molar mass of ethane (C₂H₆) is 30.07 g/mol.

2.85 g C₂H₆ × (22.4 L / 1 mol) × (1 mol / 30.07 g) = 2.123 L = 2123 mL

Volume of C₂H₆ is 2123 mL.

Answer: The volume occupied by 2.85 g ethane (C₂H₆) gas is 2123 mL.