0.00285 kg of C2H6 = 2.85 g of C2H6
Solution:
At STP, one mole of any gas occupies a volume of 22.4 L
The molar mass of ethane (C2H6) is 30.07 g/mol.
2.85 g C2H6 × (22.4 L / 1 mol) × (1 mol / 30.07 g) = 2.123 L = 2123 mL
Volume of C2H6 is 2123 mL.
Answer: The volume occupied by 2.85 g ethane (C2H6) gas is 2123 mL.
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