Solution:
Molarity = Moles of solute / litres of solution
Therefore,
Litres of solution = Moles of solute / Molarity
1)
1 mol of NaOH has a mass of 40.0 g, so
Moles of NaOH = 80.0 g NaOH × (1 mol NaOH / 40.0 g NaOH) = 2.00 mol NaOH
Litres of solution = (2.00 mol) / (2.0 M) = 1.0 L
The volume of the solution is 1.0 L
Answer (1): 1.0 L of solution.
2)
1 mol HNO3 has a mass of 63.0 g, so
Moles of HNO3 = 126 g HNO3 × (1 mol HNO3 / 63.0 g HNO3) = 2.00 mol HNO3
Litres of solution = (2.00 mol) / (6.0 M) = 0.33 L
The volume of the solution is 0.33 L
Answer (2): 0.33 L of solution.
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