Question

Calculate the molarity (M) of the following solution

2. 8.28 grams of Ca(C 5 H 9 O 2 ) 2 in 414 mL of solution.

Answer 1

Solution:

Moles of Ca(C₅H₉O₂)₂ = Mass of Ca(C₅H₉O₂)₂ / Molar mass of Ca(C₅H₉O₂)₂

The molar mass of Ca(C₅H₉O₂)₂ is 242 g/mol

Moles of Ca(C₅H₉O₂)₂ = (8.28 g) / (242 g/mol) = 0.0342 mol

Molarity is the number of moles of solute per liter of solution, which can be calculated using the following equation:

Molarity = mol solute / L of solution

Molarity of Ca(C₅H₉O₂)₂ = Moles of Ca(C₅H₉O₂)₂ / Volume of solution

Molarity of Ca(C₅H₉O₂)₂ = (0.0342 mol) / (0.414 L) = 0.0826 M

Answer: The molarity of the solution is 0.0826 M