Answer to Question #117844 in Chemistry for Elle

Question

Calculate the molarity (M) of the following solution
1. 316 grams of MgBr 2 in 859 mL of solution.

Answer 1

Solution:

Moles of MgBr₂ = Mass of MgBr₂ / Molar mass of MgBr₂

The molar mass of MgBr₂ is 184.113 g/mol

Moles of MgBr₂ = (316 g) / (184.113 g/mol) = 1.7163 mol

Molarity is the number of moles of solute per liter of solution, which can be calculated using the following equation:

Molarity = mol solute / L of solution

Molarity of MgBr₂ = Moles of MgBr₂ / Volume of solution

Molarity of MgBr₂ = (1.7163 mol) / (0.859 L) = 1.998 M = 2.00 M

Answer: The molarity of the solution is 2.00 M