a stock solution of 4.0mol/L copper 2 carbonate is available. students need to make a 1L quantity of 0.25mol/L solution. calculate the volume of stock solution needed. then calculate what you need to make 1Lof 2.5×10^6mol/L solution. show the calculations and describe the steps necessary to make the new solutions.
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Expert's answer
2020-05-24T02:37:40-0400
"M1V1 = M2V2"
M1=4.0M
M2= 0.25M
V1=?
V2=1000ml
V1=(0.25*1000)/4
V1= 62.5ml of stock solution is used to make 1000ml of o.25M solution
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