Question

a stock solution of 4.0mol/L copper 2 carbonate is available. students need to make a 1L quantity of 0.25mol/L solution. calculate the volume of stock solution needed. then calculate what you need to make 1Lof 2.5×10^6mol/L solution. show the calculations and describe the steps necessary to make the new solutions.

Answer 1

$M1V1 = M2V2$

M1=4.0M

M2= 0.25M

V1=?

V2=1000ml

V1=(0.25*1000)/4

V1= 62.5ml of stock solution is used to make 1000ml of o.25M solution