Answer to Question #116764 in Chemistry for Brenley Toth

Question

If 4.00 moles of gas and his pressure of 5.40 atm has a volume of 122 L what is the temperature

Answer 1

Solution:

The ideal gas equation, PV = nRT, can be used to calculate the temperature (T).

P = 5.40 atm

V = 122 L

n = 4.00 moles

R = 0.08206 L atm mol^-1 K^-1

T = unknown

Thus:

T = PV / nR

T = (5.40 atm × 122 L) / (4.00 mol × 0.08206 L atm mol^-1 K^-1) = 2007.068 K = 2007 K

Therefore, temperature is 2007 K.

Answer: 2007 K is the temperature.