Answer to Question #116712 in Chemistry for Brett

Question #116712
A 1.3174-g sample containing chloride salts Mg (24.30 g/mol), Hg(II)
(200.59 g/mol) & Zn (65.39 g/mol) was dissolved in 250.0 mL of soln.
A 50.00 mL aliquot was treated with 10 mL as NH3/NH4Cl buffer at pH
10.0 followed by 25.00 mL of 0.05331 M EDTA. After a few minutes of
mixing, the x’ss EDTA was back-titrated with 11.43 mL of 0.01816 M
MgCl2. The second 50.00 mL aliquot was made basic & treated with
x’ss NaCN, complexing both the Hg & Zn. The Mg in this sample req’d
16.83 mL of 0.005583 M EDTA for titration. The solution remaining at the
end pt. of this titration was treated with x’ss formaldehyde which
reacts with free CN- & Zn(CN)4

The liberated Zn2+ req’d 28.47 mL of the EDTA for titration. Calc. % of
each metal in the sample.
1
Expert's answer
2020-05-21T14:24:47-0400
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