P1 = 33 atm
V1 = 409 L
T1 = 92 K
P2 = unknown
V2 = 472 L
T2 = 19 K
Solution:
Combined Gas Law:
P1V1/T1 = P2V2/T2
or
P1V1T2 = P2V2T1
Thus:
(33 atm) × (409 L) × (19 K) = P2 × (472 L) × (92 K)
(256443 atm L K) = P2 × (43424 L K)
P2 = (256443 atm L K) / (43424 L K) = 5.906 atm = 6 atm
P2 = 6 atm
Answer: The final pressure will be 6 atm.
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