Question

2. What is the pressure in atm of 1.35 x 102 mole of oxygen gas (O2) if it is compressed in a tube with 8000 mL at 20C?

Answer 1

According to the ideal gas law:

pV = nRT,

where p - pressure, V - volume, n - number of moles, R - ideal gas constant, T - temperature.

From here:

p = nRT / V

As n = 1.35 × 10² mol, R = 0.08206 L atm / mol K, V = 8000 ml = 8 L, and T = 20 °C = 293.15 K:

p = 1.35 × 10² mol × 0.08206 L atm / mol K × 293.15 K / 8 L = 406 atm

Answer: 406 atm