Solution:
The energy, Q, needed to increase the temperature of an object of mass m, by a temperature ΔT, where the substance's specific heat is C, is given by:
Q = m × C × ΔT
m = Q / (C × ΔT)
Here,
Q = 4500 J
C = 4.186 J/(g∘C)
ΔT = Tfinal - Tinitial = 40∘C − 20∘C = 20∘C
Inputting:
m = (4500 J) / (4.186 J g-1∘C-1 × 20∘C) = 53.75 g
m(H2O) = 53.75 g
Answer: 53.75 grams of water.
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