Solution:
For Q = m × C × ΔT,
Q = amount of heat (J)
m = mass (grams)
C = specific heat (J/g°C)
ΔT = change in temperature (°C)
Q = 4500 J
C(H2O) = 4.186 J/g°C
ΔT = Tfinal - Tinitial = (40 - 20)°C = 20°C
Thus,
m = Q / (C × ΔT)
m = (4500 J) / (4.186 J/g°C × 20°C) = 53.75 g
m(H2O) = 53.75 g
Answer: 53.75 grams of water.
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