Solution:
[H3O+] = 1.905×10−5 mol/L
The hydroxide ion concentration can be calculated using the Kw constant:
Kw = [H3O+]×[OH−] = 1.0×10-14
Therefore,
[OH−] = Kw / [H3O+]
[OH−] = (1.0×10−14) / (1.905×10−5) = 5.249×10−10
[OH−] = 5.249×10−10 M
Answer: [OH−] = 5.249×10−10 M
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