Answer to Question #115061 in Chemistry for Raf

Question

What will be the volume of a 3.0M solution using 1.0g of NaCl?

Answer 1

The molarity of the solution $c$ (3.0 M, or mol/L) is defined as:

$c = \frac{n}{V}$ ,

where $n$ is the number of the moles of the solute (NaCl) and $V$ is the volume of the solution. Therefore, the volume of the solution can be expressed from this formulae as:

$V = \frac{n}{c}$ .

Let's calculate the number of the moles in 1.0 g of NaCl. The number of the moles can be calculated from the ratio of the mass of NaCl ($m=$ 1.0 g) and the molar mass of NaCl ($M =$ 58.44 g/mol).

$n = m/M = 1.0/58.44 = 0.017$ mol

Finally, the volume of the solution:

$V = \frac{0.017}{3.0} = 0.0057$ L, or 5.7 mL.

Answer: the volume of a 3.0M solution using 1.0g of NaCl will be 5.7 mL.