Question

Calculate the mass in gram of copper that Will be deposited by dissolving 6.5 of zinc in Cuso4

Answer 1

Let's start by writing the balanced reaction equation:

Zn + CuSO₄ $\rightarrow$ Cu + ZnSO₄.

In condition when there is enough of CuSO₄, 1 mole of zinc produces 1 mole of copper:

$n(Zn) = n(Cu)$.

The number of the moles of zinc is the ratio of its mass $m$ to its molar mass $M$  (65.39 g/mol):

$n(Zn) = m/M = \frac{6.5}{65.39} = 0.1$ mol.

Using the same formula to express the mass of copper (the molecular weight $M$ of copper is $58.93$ g/mol):

$m(Cu) = n·M = 0.1·58.93 = 5.9$ g.

Answer: the mass in gram of copper that will be deposited by dissolving 6.5 of zinc in CuSO₄ is 5.9 g.