Answer to Question #113507 in Chemistry for robyn

Question

a cylinder of helium gas has a volume of 1.0 L. The gas in the cylinder exerts a pressure of 800 kPa at 30 degrees. What volume would this gas occupy at SATP

Answer 1

SATP - Standard Ambient Temperature and Pressure.

SATP: T = 25^∘C and P = 1 bar.

P₁ = 800 kPa;

V₁ = 1.0 L;

T₁ = 30^∘C = 303 K;

P₂ = 1 bar = 100 kPa;

V₂ = unknown;

T₂ = 25^∘C = 298 K.

Solution:

The Combined Gas Law can be expressed as:

P₁V₁ / T₁ = P₂V₂ / T₂

Cross-multiply to clear the fractions:

P₁V₁T₂ = P₂V₂T₁

Divide to isolate V₂:

V₂ = (P₁V₁T₂) / (P₂T₁)

Plug in the numbers and solve for V₂:

V₂ = (800 kPa × 1.0 L × 298 K) / (100 kPa × 303 K) = 7.868 L

V₂ = 7.87 L

Answer: The volume of gas will be 7.87 L at SATP.