The molecular weight of glucose equals:
Mr(C6H12O6) = (12 × 6) + (12 × 1) + (16 × 6) = 180 g/mol
As a glucose molecule contains six carbons, the molecular weight of those carbons equals:
Mr(C6) = 72 g/mol
As 180 g/mol corresponds to 200.00 g of glucose and 72 g/mol corresponds to the unknown mass of carbon in glucose:
180 g/mol / 72 g/mol = 200.00 g / m(carbon)
From here:
m(carbon) = 72 g/mol × 200.00 g / 180 g/mol = 80 g
Answer: 80 g
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