Solution:
1 mol of Zn has mass of 65.38 g.
The amount of Zn is (28.0 g) / (65.38 g/mol) = 0.428 mol.
The balanced chemical equation:
Zn + H2SO4 = ZnSO4 + H2
According to the chemical equation: n(Zn) = n(H2).
The amount of H2 produced is the same as the amount of Zn consumed (0.428 mol).
n(H2) = 0.428 mol.
1 mol of ideal gas will occupy 22.4 L at STP.
The H2 will occupy 0.428 mol × 22.4 L/mol = 9.5872 L = 9.59 L.
V(H2) = 9.59 L.
Answer: 9.59 L of hydrogen (H2) can be produced.
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