Question

The molecular weight of glucose,

C6H12O6\text{C}_6 \text H_{12} \text O_6

C

6

​


H

12

​


O

6

​


start text, C, end text, start subscript, 6, end subscript, start text, H, end text, start subscript, 12, end subscript, start text, O, end text, start subscript, 6, end subscript

, is

180.16 gmol180.16\,\dfrac{\text g}{\text{mol}}

180.16

mol


g

​


180, point, 16, start fraction, start text, g, end text, divided by, start text, m, o, l, end text, end fraction

.

How many moles of glucose are in

19.1 g19.1\,\text g

19.1g

19, point, 1, start text, g, end text

of glucose?

Answer 1

Correct task: The molecular weight of glucose, C₆H₁₂O₆, is 180.16 g/mol.

How many moles of glucose are in 19.1g of glucose?

Solution:

Moles of glucose = Mass of glucose / Molecular weight of glucose

n(glucose) = m(glucose) / M(glucose)

n(glucose) = 19.1 g C₆H₁₂O₆ × (1 mol C₆H₁₂O₆ / 180.16 g C₆H₁₂O₆) = 0.106 mol C₆H₁₂O₆

Moles of glucose (C₆H₁₂O₆) = 0.106 mol. 

Answer: 0.106 mol of glucose (C₆H₁₂O₆) are in 19.1 g.