Answer to Question #111580 in Chemistry for shouq

Question

The molecular weight of glucose,
C6H12O6\text{C}_6 \text H_{12} \text O_6
C
6
​

H
12
​

O
6
​

start text, C, end text, start subscript, 6, end subscript, start text, H, end text, start subscript, 12, end subscript, start text, O, end text, start subscript, 6, end subscript
, is
180.16 gmol180.16\,\dfrac{\text g}{\text{mol}}
180.16
mol

g
​

180, point, 16, start fraction, start text, g, end text, divided by, start text, m, o, l, end text, end fraction
.
How many moles of glucose are in
19.1 g19.1\,\text g
19.1g
19, point, 1, start text, g, end text
of glucose?

Answer 1

Correct task: The molecular weight of glucose, C₆H₁₂O₆, is 180.16 g/mol.

How many moles of glucose are in 19.1g of glucose?

Solution:

Moles of glucose = Mass of glucose / Molecular weight of glucose

n(glucose) = m(glucose) / M(glucose)

n(glucose) = 19.1 g C₆H₁₂O₆ × (1 mol C₆H₁₂O₆ / 180.16 g C₆H₁₂O₆) = 0.106 mol C₆H₁₂O₆

Moles of glucose (C₆H₁₂O₆) = 0.106 mol. 

Answer: 0.106 mol of glucose (C₆H₁₂O₆) are in 19.1 g.