Equal volumes of oxygen and nitrogen were allowed to diffuse under the similar conditions of temperature and pressure.If oxygen took 18s to diffuse , determine the time that would be taken by nitrogen
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Expert's answer
2020-04-20T15:06:14-0400
According to Graham's law of diffusion, the ratio of the rates of diffusion of two gases (rO2,rN2) is the square root of the inverse ratio of their molar masses (MO2 , MN2 ):
rN2rO2=MO2MN2 .
The rate of diffusion is the amount of gas passed through an area per unit time. Therefore, it is inversely proportional to the time of diffusion t :
rN2rO2=tO2tN2 .
Combine the equations above:
MO2MN2=tO2tN2 .
The molar masses of O2 and N2 are 32.00 g/mol and 28.01 g/mol, respectively. The time taken by nitrogen is:
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