Question

Calculate the number of mols of copper II sulphate in 50.0cm3 of 1.00moldm3 solution

Answer 1

According to the equation:

M = n / V

where M - molar concentration, n - number of moles, V - volume.

From here:

n = M × V

As 1.00 mol/dm³ = 1.00 mol/L and 50.0 cm³ = 50.0 mL, the number of moles of copper II sulphate equals:

n(CuSO₄) = M(CuSO₄) × V(CuSO₄) = 1.00 mol/L × 50.0 mL = 1.00 mol/L × 50.0 × 10^-3 L = 0.0500 mol

Answer: 0.0500 mol