According to the equation:
M = n / V
where M - molar concentration, n - number of moles, V - volume.
From here:
n = M × V
As 1.00 mol/dm3 = 1.00 mol/L and 50.0 cm3 = 50.0 mL, the number of moles of copper II sulphate equals:
n(CuSO4) = M(CuSO4) × V(CuSO4) = 1.00 mol/L × 50.0 mL = 1.00 mol/L × 50.0 × 10-3 L = 0.0500 mol
Answer: 0.0500 mol
Comments
Leave a comment