Question

A sample of gas has a pressure of 4.5 atm and a temperature of 325 K. What will be a new pressure if the temperature is

raised to 500K?

Law being used: ___________ FORMULA WORK ANSWER

Given 1:__________

Given 2:__________

Given 3:__________

Answer 1

Solution:

Volume is constant

Law being used: Gay-Lussac’s Law

Given 1: __ P₁ = 4.5 atm __

Given 2: __ T₁ = 325 K __

Given 3: __T₂ = 500 K __

FORMULA:

P₁ / T₁ = P₂ / T₂

WORK:

P₁*T₂ = P₂*T₁

(4.5 atm) * (500 K) = (P₂) * (325 K)

P₂ = (4.5 * 500) / 325 = 6.923 atm

P₂ = 6.923 atm = 6.9 atm

ANSWER: P₂ = 6.9 atm.