Question #109978
The pressure of a sample of helium in a 1.0L container is 0.98 atm. What is the new pressure if the sample is placed in a 2.0
L container?
Law being used: ___________ FORMULA WORK ANSWER
Given 1:__________
Given 2:__________
Given 3:__________
L container?
Law being used: ___________ FORMULA WORK ANSWER
Given 1:__________
Given 2:__________
Given 3:__________
Expert's answer
Solution:
Temperature is constant
Law being used: Boyle’s Law
Given 1: __ P1 = 0.98 atm __
Given 2: __ V1 = 1.0 L __
Given 3: __V2 = 2.0 L __
FORMULA:
P1V1 = P2V2
WORK:
P1 * V1 = P2 * V2
(0.98 atm) * (1.0 L) = (P2) * (2.0 L)
P2 = (0.98 * 1.0) / 2.0 = 0.49 atm
P2 = 0.49 atm
ANSWER: P2 = 0.49 atm.
