Answer to Question #109978 in Chemistry for Elle

Question

The pressure of a sample of helium in a 1.0L container is 0.98 atm. What is the new pressure if the sample is placed in a 2.0
L container?
Law being used: ___________ FORMULA WORK ANSWER
Given 1:__________
Given 2:__________
Given 3:__________

Answer 1

Solution:

Temperature is constant

Law being used: Boyle’s Law

Given 1: __ P₁ = 0.98 atm __

Given 2: __ V₁ = 1.0 L __

Given 3: __V₂ = 2.0 L __

FORMULA:

P₁V₁ = P₂V₂

WORK:

P₁ * V₁ = P₂ * V₂

(0.98 atm) * (1.0 L) = (P₂) * (2.0 L)

P₂ = (0.98 * 1.0) / 2.0 = 0.49 atm

P₂ = 0.49 atm

ANSWER: P₂ = 0.49 atm.