Answer to Question #109754 in Chemistry for Nounaude

Question

How many moles of nitrogen dioxide, NO2, are needed to react with 2.83 moles of water, H2O?



4 NO2(g) + 6 H2O(g) → 7 O2(g) + 4 NH3(g)

Answer 1

n(H₂O) = 2.83 moles.

Solution:

The equation of a chemical reaction:

4NO₂(g) + 6H₂O(g) → 7O₂(g) + 4NH₃(g)

According to the reaction equation: n(NO₂)/4 = n(H₂O)/6.

n(NO₂) = 4*n(H₂O)/6;

n(NO₂) = (4 * 2.83 moles) / 6 = 1.8867 moles = 1.89 moles

n(NO₂) = 1.89 moles.

Answer: 1.89 moles of nitrogen dioxide (NO₂).