Answer to Question #109103 in Chemistry for david

Question

a mole of bowling balls would cover the surface of the earth to a depth of how much?

Answer 1

Bowling ball

Diameter: 25.4 cm

Surface area of the widest part: A = πr²

A = 3.14 x (25.4 : 2)² = 39.878 cm²

Surface of the Earth:

5.1 x 10⁸ km = 5.1 x 10¹⁸ cm

Area of a mole of bowling ball =

SA of ball x 1 mole = 39.878 x 6.022 x 10²³ = 240.15 x 10²³ cm²

Number of times covering the Earth =

SA of 1 mole of bowling ball : SA of Earth = 240.15 x 10²³ : 5.1 x 10¹⁸ = 47 x 10⁵

Depth it would cover to = # of times it would cover the Earth x bowling ball diameter = 47 x 10⁵ x 25.4 = 1.2 x 10⁸ cm