(234 91)Pa --> (A Z)X + (4 2)He
Solution:
1) 234 = A + 4;
A = 234 - 4;
A = 230.
2) 91 = Z + 2;
Z = 91 - 2;
Z = 89.
Therefore,
(A Z)X = (230 89)Ac = actinium-230
(234 91)Pa --> (230 89)Ac + (4 2)He
Answer: (230 89)Ac.
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