Solution:
1 mole of any gas occupies 22.4 dm3 at STP (standard temperature and pressure, taken as 0°C and 1 atmosphere pressure).
Then,
(67.2 mol of H2) * (22.4 dm3/mol) = 1505.28 dm3 = 1505.28 L.
Answer: 67.2 mol of H2 will occupy a volume of 1505.28 dm3.
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