Answer to Question #108552 in Chemistry for ern

Question

What is the pOH of a KOH solution that has [OH− ] = 5.81 × 10−3 M?

Answer 1

Solution:

KOH is a strong base in aqueous media therefore it ionizes 100%.

KOH = K⁺ + OH⁻

This means that

[OH⁻] = [KOH] = 5.81*10⁻³ M.

pOH = −log[OH⁻].

Therefore,

pOH = −log[OH⁻] = −log[5.81*10⁻³] = 2.2358 = 2.24

pOH = 2.24

Answer: 2.24 is the pOH of a KOH solution that has [OH⁻] = 5.81*10⁻³ M.