Answer to Question #106595 in Chemistry for Jordan

Question

A chemist needs to prepare 2.50 L of 0.100 M ammonia. How much concentrated (14.8 M) ammonia does he need?

Answer 1

The ratios between concentrations and volumes of the initial and final solutions can be described as following:

M_initial / M_final = V_final / V_initial

where Minitial - molarity of a concentrated solution, Mfinal - molarity of a final solution, Vinitial - volume of a concentrated solution, Vfinal - volume of a final solution

From here:

V_initial = M_final × V_final / M_initial = 2.50 L × 0.100 M / 14.8 M = 0.0169 L = 16.9 mL

Answer: 16.9 mL