amount of heat = q = 4000 J;
T1 = 98℃;
T2 = 199℃;
change in temperature = ΔT = T2 - T1 = 199℃ - 98℃ = 101℃;
specific heat of Cu = c = 0.385 J/g ℃.
Solution:
The relationship between specific heat capacity (c), energy in joules (q), mass in grams (m) and temperature change (ΔT) express as a mathematical equation:
q = m × c × ΔT
Then,
m(Cu) = q / (c × ΔT) = (4000 J) / (0.385 J/g ℃ * 101℃) = (4000 J) / (38.885 J/g) = 102.867 g
m(Cu) = 102.867 g.
Answer: 102.867 grams is the mass of the copper sample.
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