Question

How many liters of ammonia gas is generated with 4.50 L of nitrogen gas and excess hydrogen gas?

Answer 1

The formation of ammonia is described by the following reaction:

N₂ + 3H₂ = 2NH₃

As 1 mole of any gas occupies 22.4 L at standard conditions, than:

V(NH₃) = V (N₂) × (2 × 22.4 L) / 22.4 = 4.50 L × (2 × 22.4 L) / 22.4 L = 9.0 L

Answer: 9.0 L of ammonia