Applying "pV=nRT"
"n=\\frac{pV}{RT}"
"n=\\frac{90\\times500}{496\\times0.082} =1106 mole\/min" for ammonia
"n=\\frac{45\\times600}{496\\times0.082} =664mole \/min" for carbon-dioxide
Here if we compare the stochiometric coefficients of ammonia and carbon dioxide then it is 2:1
then here the limiting reagent is ammonia
As the ratio of stochiometric coefficients of ammonia and urea is in the ratio 2:1
So urea produced will be half of ammonia=1106/2 mole/min =553 mole/min
urea produced in mass = 553*60 =33180grams/min=33.18 kg/min
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