Answer to Question #104144 in Chemistry for Alia

Question

Based on the included solubility curve,at what temperature is 378.5 g of lead(II) nitrate completely soluble in 456 ml of water to create a saturated solution?

Answer 1

There is no solubility curve included! However, there is solubility vs. temperature data in the following site - https://en.wikipedia.org/wiki/Solubility_table. Thus, 378.5 g of the lead nitrate per 456 mL is some 378.5g*100mL/456mL = 83 g per 100 mL of water. According to the information given in https://en.wikipedia.org/wiki/Solubility_table it is nearly 50 C.