Answer to Question #103412 in Chemistry for Nick

Question

How many grams of O2 are produced from the decomposition of 3.5 mil KCLO3?

Answer 1

Potassium chlorate undergoes according to the following equation:

KCLO₃ → KCl + O₂

As 3.5 mol of KCLO₃ are used, the same number of moles of oxygen are produced in the reaction. As a result:

m (O₂) = n (O₂) × Mr(O₂) = 3.5 mol × 32 g/mol = 112 g

Answer: 112 g