The given reaction can be written as following:
Fe2O3 + 3C = 2Fe + 2CO
(a) To answer the first question, the limiting reagent should be determined. For the purpose, the number of moles of each reactant must be estimated:
n(Fe2O3) = m / Mr = 20.5 × 106 g / 160 g/mol = 1.23 × 105 mol
n(C) = m / Mr = 2.84 × 106 g / 3 × 12 g/mol = 7.9 × 104 mol
As carbon is a limiting reagent, more coke should be ordered.
(b) As carbon is a limiting reagent, 7.9 × 104 mol of iron will be produced. As a result:
m(Fe) = n(Fe) × 2 × Mr (Fe) = 7.9 × 104 mol × 2 × 56 g/mol = 8.85 × 106 g = 8.85 megagrams
Answer: (a) coke should be ordered, (b) 8.85 megagrams
Comments
Leave a comment