Task:
A compound contains 6.0 g of carbon and 8.0 g of oxygen. The percent composition of the compound is:
Solution:
m(carbon) = 6.0 g;
m(oxygen) = 8.0 g
total weight of the compound = m(compound) = m(carbon) + m(oxygen);
m(compound) = 6.0 g + 8.0 g = 14.0 g;
Hence,
w(carbon) = m(carbon) / m(compound) = 6.0 / 14.0 = 0.4286 or 42.86%.
w(oxygen) = m(oxygen) / m(compound) = 8.0 / 14.0 = 0.5714 or 57.14%.
Answer: The percent composition of the compound is: 42.86% carbon and 57.14% oxygen.
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