Answer to Question #102006 in Chemistry for myuki dhea inaba

Question

what is the mass in grams of NH4Cl present in 50.0ml of a 0.800 M NH4Cl solution?

Answer 1

Answer on Question #102006 – Chemistry – Other

Task:

What is the mass in grams of NH₄Cl present in 50.0ml of a 0.800 M NH₄Cl solution?

Solution:

1) Molarity (M) is the concentration of a solution expressed as the number of moles of solute per liter of solution:

Molarity (M) = moles solute / liters solution = C_M = n / V

Then,

C_M(NH₄Cl) = n(NH₄Cl) / V(NH₄Cl);

n(NH₄Cl) = C_M(NH₄Cl) * V(NH₄Cl) = 0.800 M * 0.050 L = 0.04 moles.

2) Molar mass of NH4Cl:

M(NH₄Cl) = Ar(N) + 4*Ar(H) + Ar(Cl) = 14 +4*1 + 35.5 = 53.5 (g/mol).

3) The relationship between molar mass, mass and moles can be expressed as a mathematical equation as shown below:

n = m / M

Then,

n(NH₄Cl) = m(NH₄Cl) / M(NH₄Cl);

m(NH₄Cl) = n(NH₄Cl) * M(NH₄Cl) = 0.04 mol * 53.5 g/mol = 2.14 g

m(NH₄Cl) = 2.140 g.

Answer: 2.140 g is the mass in grams of NH₄Cl.