Magnesium hydroxide dissociates according to the following equation:
Mg(OH)2 ⇌ Mg2+ + 2OH-
Solubility product (Ksp) of magnesium hydroxide at standard conditions equals:
Ksp = 5.61 10¯12
As a result:
Ksp = [Mg2+] × [OH-]2
From here:
Ksp = (s) × (2s)2 = 4s3
s = (4Ksp)1/3 = 1.12 × 10-4 M
As a result, concentration of hydroxide ions equals:
[OH¯] = 2 × 1.12 × 10-4 M = 2.24 × 10-4 M
From here:
pOH = - log (2.24 × 10-4) = 3.650
pH = 14 - 3.650 = 10.350
Answer: 10.350
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