Question

A salt solution containing ferrous ion was titrated with (9.80000x10^-3) M KMnO4 solution. The mean of 3 acceptable, corrected titration values was (1.400x10^1) mL. Calculate the moles of ferrous ion reacting in each titration portion.

Answer 1

5Fe²⁺+MnO₄^-+8H⁺$\to$ 5Fe³⁺+Mn²⁺+4H₂O

1.400x10^1(mL)=0.014L

n(KMnO₄)=9.80000x10^-3(M)*0.014(L)=1.372*10^-4(moles)

n(Fe²⁺)=1.372*10^-4(moles)*5=6.86*10^-4(moles).