Task:
What mass of sulphuric acid contains 1.4 mol of Oxygen?
Solution:
1) H2SO4 --> 4O
n(H2SO4) = n(O)/4;
n(H2SO4) = 1.4 mol / 4 = 0.35 mol;
2) n = m / M;
m = n * M
M(H2SO4) = 2*Ar(H) + Ar(S) + 4*Ar(O) = 2*1 + 32 + 4*16 = 98 (g/mol).
m(H2SO4) = n(H2SO4) * M(H2SO4) = 0.35 mol * 98 g/mol = 34.3 g.
m(H2SO4) = 34.3 g.
Answer: 34.3 grams of sulphuric acid contains 1.4 mol of Oxygen.
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