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If 12.3 g of Cu is deposited at the cathode of an electrolytic cell after 5.50 h, what was the current used?


A voltaic cell is constructed based on the following reaction and initial concentrations:

Fe2+(0.0050 M) + Ag+(2.0 M) ↔ Fe3+(0.0050 M) + Ag(s)


Calculate [Fe2+] when the cell reaction reaches equilibrium.


A common reference electrode consists of a silver wire coated with AgCl(s) and immersed in 1 M KCl (pictured in Question 7).

AgCl (s) + e- → Ag(s) + Cl(1 M)      E° = 0.2223 V

Why would this electrode be easier to use than a standard hydrogen electrode?


(a) It is a less spontaneous system than the S.H.E.

(b) It does not use gases, so it is easier to handle.

(c) The S.H.E. is more standard

(d) It yields a lower Ecell value.


A common reference electrode consists of a silver wire coated with AgCl(s) and immersed in 1 M KCl (pictured in Question 7).

AgCl (s) + e- → Ag(s) + Cl(1 M)      E° = 0.2223 V


What is Ecell when this electrode is a cathode in combination with a standard zinc electrode as an anode?


When Pt electrodes are used in the electrolysis of KI(aq), a number of reactions are possible at the electrodes. 

Using a standard reduction potentials table, predict which reaction is most likely to occur at the cathode.


When Pt electrodes are used in the electrolysis of KI(aq), a number of reactions are possible at the electrodes. 

Using a standard reduction potentials table, predict which reaction is most likely to occur at the anode


If 12.3 g of Cu is deposited at the cathode of an electrolytic cell after 5.50 h, what was the current used?


 Solutions if they are left standing long enough which separate out is known as  


There are two separate phases, one with a composition of 12% phenol and the other with a composition of 60% phenol, from a 210 gram phenol-water mixture with 35% phenol at 60oC. Calculate the masses of these phases.


1.42 gram mixture of CaCO3 and MgCO3 is dissolved in 160 mL of N/4 HCl and the volume of solution is made 250 mL by adding water. 10 mL of this solution requires 12 mL of N/30 NaOH for complete neutralisation. Calculate the percentage of each component in the original mixture.


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