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Topic: Electrode Potential and Electrochemical Cells

question 1

The diagram below shows the experiment setup for a typical electrochemical cell that contains two standard half cells. The cell operates according to the reaction represented by the following equation

Zn(s) + Ni2+ (aq) โ€”> NI(s) + Zn2+ (aq)


a) identify M and M2+ in the diagram? ( marks)

b) indicate which of the metal electrodes in the cathode. Write the balanced equation for the reaction that occurs in the half-cell containing the cathode. (2 marks).

c) Describe what would happen in the cell voltage if the said bridge was removed. Explain the reason for this. ( 2 marks)

please answers all the questions and with detailed answers with explanation please ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ


Topic:Acid and Bases

Q1

a) calculate the pH of the following solutions:

i) 0.002 mol dm-3 KOH (2 marks)

ii) 0.10 mol dm-3 C6H5COOH ( K of benzoin acid = 6.3 x 10-5 mol dm-3 ) ( 4 marks)


b) The pH of a 0.10 mol dm-3 solution of a weak mono proton acid, HA , is 2.85. Determine the K of the acid. ( 2 marks)


c) A 500 cm3 solution containing 1.8g of a weak acid HA has a pH of 3.5. Calculate the molar mass of the acid, given that it has a value for K of 2.0 x 10 -6mol dm . ( 5 marks)


please answers all the questions with detailed explanation and steps ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ


. Under 298 K and 101.325 kpa, the defined entropy of diamond and graphite is 2.45 Jยท mol-1ยทK-1 and 5.71 Jยท mol-1ยทK-1, respectively.ย Their standard combustion heat are

-395.40 kJ ยท mol-1and -393.51 kJยทmol-1, respectively.ย Calculate the value of

Graphiteย ย ย ย ย ย ย ย ย ย Diamond

under these conditions, and explain which crystal is more stable at these conditions.

ย 


Acids and Bases

Q1

a) State weather the following species can behave as an acid, as a base , or both:

(i) NH4+

(ii) HCIO4

(iii) CO32-


all 1 mark


b) in the following reaction, identify the reactant that acts as an acid:

CH3COOH (aq) + HCIO4 (aq) โ€”-> <โ€”- CH2COOH2+ (aq) + CIO4 (aq) (1 mark)


c) identify the acid-base conjugate pairs in the following reactions:

HCO3- (aq) + H3O+ (aq) โ€”-> <โ€”- CO2 (g) + H2O + H2O (I). ( 2 marks )


please detailed answers with explanation please๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ



Equilibrium Constant

Q1

for both of the following equilibria, write the expression for the equilibrium constant Kc and state itโ€™s units:

i) H2(g) + I2 (g) โ€”-> <โ€”โ€” 2HI (g) (2 marks)

ii) 2SO2 (g) + O2(g) โ€”โ€”> <โ€”โ€” 2SO2 (g) (2 marks)

Q2

the reaction for the formation of hydrogen bromine does not go to completion but reaches an equilibrium, as shown:

H2(g) + Br2 โ€”-> <โ€”โ€” 2HBr(g)

a mixture of 1.9 mol of H2 and 1.9 of Br was prepared and allowed to reach equilibrium in a closed vessel on 250 cm3 capacity. The resulting equilibrium mixture was found to contain 3.0 moles of HBr. Calculate the value of K. (3 marks please detailed answers with explanation๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ)


Topic: Rate Equations

Question 1

Twi compounds, A and B , react in the following way:

A + 3B โ€”> AB3.

using the data below, derive the rate equation for this reaction and explain your reasoning.(4 marks)

b) Use the experimental data provided below to determine the rate constant. ( 3 marks)

data:

  • Experiment 1 ,Initial (A) ( mol dm-3) 0.100 , Initial (B) (mol dm3 ) 0.100 , Initial rate of formation of AB (mol dm-3)0.002.
  • Experiment 2, Initial (A) (mol dm-3) 0.100 , Initial (B) ( mol dm-3) 0.200, Initial rate of formation of AB3 ( mol dm-3) 0.008.
  • Experiment 3 , Initial (A) (mol dm-3) 0.100 , Initial (B) (mol dm-3) 0.300, Initial rate of formation of AB3 (mol dm-3) 0.018.
  • Experiment 4, Initial (A) ( mol dm-3) 0.200 , Initial (B) ( mol dm-3) 0.100 , Initial rate of formation of AB ( mol dm-3) 0.004.
  • Experiment 5, Initial (A) (mol dm-3) 0.300 , Initial (B) (mol dm-3) 0.100 , Initial rate of formation of AB (mol dm-3) 0.006.

Rate Equation

Q1

a) Explain the meaning of the term rate of reaction (1 mark)

b) The following data is provided for the reaction

2NO(g) + H2(g) โ€”โ€”> N2O (g) + H2O

  • Initial (NO) (mol dm-3 ) 0.70 , Initial (H) ( mol dm-3) 0.42, Initial rate ( mol dm-3 s-1) 4.0 x 10-3.


  • Initial (NO) ( mol dm-3) 1.40, Initial (H) (mol dm-3) 0.42, initial rate ( mol dm-3 s-1) 1.6 x 10-2.


  • Initial (NO) (mol dm-3)1.40, Initial (H2) ( mol dm-3) 0.84, Initial rate (mol dm-3 s-1) 1.6 x 10-2.


(I)use the data to derive the order of reaction with respect to H and NO and explain your workings? (4 marks)

(II)Derive the overall order? (1 mark)

(III)Give the rate equation? (1 mark)

(IV)Calculate the value of k? (2 marks)


please detailed answers with expiation for everything please๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ



Thermodynamics

Q3

using the following data, calculate the change in entropy when one mole of ammonia is formed from its elements:

N(g) = 191.6 J K mol

H(g) = 130.6 J K mol

NH (g) = 192.3 J K mol


(3 marks please answers with detailed explanation please ๐Ÿ™๐Ÿพ )


Thermodynamics

Q2

using the following data, calculate the enthalpy of solution chloride:


Enthalpy of hydration of Li+ = -520 kJ mol-1

Enthalpy of hydration of CI- = -364 kJmol -1

Lattice enthalpy LiCI = -860 kJ mol-1


(2 marks)

please detailed and correct answers ๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ


Topi:Thermodynamicsย 

Q1

Given the following bond energy data: (Bond and AHb kJmol-1)

  • Bond C-H and AHb +413 kJmol-1
  • Bond C-Br and AHb +285 kJmol-1
  • Bond C-CI and AHb +328 kJmol-1
  • Bond Br-Br and AHb +193 kJmol-1
  • Bond C-C and AHb +347 kJmol-1


  • Bond C=C and AHb +611 kJmol-1


  • Bond H-CI and AHb +428 kJmol-1
  • Bond CI-CI and AHb +428 kJmol-1

Calculate the theoretical enthalpy changes for the following reactions:

a) C2H4 + Br2 โ€”> C2H4Br2

b) CH4 + CI2 โ€”โ€”> CH3CI + HCI

please detailed/top answers๐Ÿ™๐Ÿพ๐Ÿ™๐Ÿพ


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