Let mole fraction of A in liquid phase is xa and B in liquid phase is xb=1−xa
Then according to question,
0.55=0.45xa+0.65(1−xa)
0.2xa=0.1orxa=0.5
xb=1−xa=0.5 Composition in vapour phase will be-
pa=0.45xa=0.225 barpb=0.65xb=0.325 bar
Mole fraction of A in vapour phase , ya=0.550.225=0.4090
Mole fraction of B in vapour phase,yb=0.5500.325=0.5909
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