Question #97018
Calculate the molar enthalpy of vaporization of a liquid which boils at 120°C.
1
Expert's answer
2019-10-25T06:26:01-0400

Using Clausius-Clayperon equation lnP=HRTlnP=-\frac{∆H}{RT}

P=105PaP=10^5Pa

H=37.624KJmol∆H=37.624\frac{KJ}{mol}


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