Using Clausius-Clayperon equation lnP=−∆HRTlnP=-\frac{∆H}{RT}lnP=−RT∆H
P=105PaP=10^5PaP=105Pa
∆H=37.624KJmol∆H=37.624\frac{KJ}{mol}∆H=37.624molKJ
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